82 is your answer , I subtracted 52-40 and got 12 , so I know that the RC side is 12 more than 70.

Let's simplify ~






value x lies between :

if the value of x is taken -5


if value of x is taken as 5


So, the possible values of the required expression lies between ~

I hope you understood the whole procedure. let me know if you have any doubts in given steps ~
There are only 23=823=8 possible ways to arrange the genders boy/girl, with repetition. Since the probability of boy and girl are equal, the probability of each of these arrangements are also equal. We can therefore count the number of possible "good" answers, and divide by 8.
There are 3 possible ways to have 1 boy, that being "first/second/third child is boy", so the probability of exactly 1 boy is indeed 3838.
Having at most 2 girls is the opposite of having three girls, so since there are only one way of having three girls, there must be 8−1=78−1=7 ways of having at most two girls, so the probability of at most two girls is indeed 78
The formal name for the property
of equality that
allows one to add the same quantity to both sides
of an equation.
This is one
of the most commonly used properties for solving equations.
The formula tells us that if a = b, then a + c = b + c. The letters a and b stand for two separate numbers, our two twins, and the letter c
stands for what we give to each twin to keep them matching. So, for
example, if we add 1 to the left side of the equation, we must also add 1
to the right side of the equation. By doing this, we keep the equation,
the twins, the same.
Answer: correct choice is B.