Question

Cuanto me da como resultado

Answer 1

Step-by-step explanation:

1) $(-4)^2{\cdot}(-4)$

We know that, $a^x{\cdot}a^y=a^{x+y}$

$(-4)^2{\cdot}(-4)=(-4)^{2+1}\\\\=(-4)^3\\\\=64$

2) $(-2)^5{\cdot} (-2)^3$

Again using above property,

$(-2)^5{\cdot} (-2)^3=(-2)^8\\\\=256$

3) $5^{-3}$

We know that,

$a^{-x}=\dfrac{1}{a^x}$

So,

$5^{-3}=\dfrac{1}{5^3}\\\\=\dfrac{1}{125}$

4) $2.5^2=2.5\times 2.5\\\\=6.25$

Hence, this is the required solution.