All categories

3 years ago

Express {x+1}{2x-3} as a trinomial.

Mathematics

1 answer:

Marizza181 [45]3 years ago

6 0

Answer:

$2x^2 + 5x + 3$

Step-by-step explanation:

First, expand the original equation:

(x + 1)(2x + 3)

$2x^2 + 3x + 2x + 3$

Now simplify:

$2x^2 + 5x + 3$

And that's your answer!

You might be interested in

If tan = 12/5 and cos = -5/13, then what is sin?

Over [174]

9514 1404 393

Answer:

sin -12/13

Step-by-step explanation:

You can use the identity ...

tan = sin/cos

to solve for sine:

sin = cos·tan

sin = (-5/13)(12/5) =

sin -12/13

4 0

3 years ago

) The National Highway Traffic Safety Administration collects data on seat-belt use and publishes results in the document Occupa

asambeis [7]

Answer:

We conclude that there is a difference in seat belt use.

Step-by-step explanation:

We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.

Let $p_1$ = population proportion of drivers 16-24 years old who buckle up .

$p_2$ = population proportion of drivers 25-69 years old who buckle up .

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 {means that there is no significant difference in seat belt use}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq$ 0 {means that there is a difference in seat belt use}

The test statistics that would be used here Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers 16-24 years old who buckle up = 79%

$\hat p_2$ = sample proportion of drivers 25-69 years old who buckle up = $\frac{924}{1100}$ = 84%

$n_1$ = sample of 16-24 years old drivers = 1000

$n_2$ = sample of 25-69 years old drivers = 1100

So, test statistics = $\frac{(0.79-0.84)-(0)}{\sqrt{\frac{0.79(1-0.79)}{1000}+\frac{0.84(1-0.84)}{1100} } }$

= -2.946

The value of z test statistics is -2.946.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a difference in seat belt use.

4 0

3 years ago

Let f and g be linear functions with equations f(x) = m1x + b1 and g(x) = m2x + b2.

MariettaO [177]

F(x) = m1x + b1
g(x) = m2x + b2

f(g(x)) = f(m2x + b2) = m1(m2x + b2) + b1 = m1m2x + b2 + b1

a.) f of g is also a linear function.

b.) slope is m1m2

8 0

3 years ago

Help me pleasseeeee!!! its about algebraic properties of limits!

s2008m [1.1K]

$\text{Hello there! :)}$

$3. \sqrt{2} \\\\\text{4. 0}\\\\\text{5. dne}$

$\text{To find the overall limit, they must approach the same y-value from each side:}$

$\\\\3. \lim_{x \to \frac{\pi }{4} } 2sinx ={\sqrt{2}$

$\text{Therefore:}\\\\3. \lim_{x \to \frac{\pi }{4} } f(x)= {\sqrt{2} }$

$\text{For this question, evaluate the limit from the RIGHT-HAND side:}\\\\4. \lim_{x \to \pi +} f(x)\\\\ \text{Use the equation tanx to evaluate since it involves values greater than \pi:}\\\\$

$\lim_{x \to \pi +} tanx = 0\\\\\text{So:}\\\\ \lim_{x \to \pi +} f(x) = 0$

$5. \\\\\text{Evaluate the overall limit. Make sure both sides approach the same y=value:}\\\\ \lim_{x \to \pi } 2cosx= -2\\\\ \lim_{x \to \pi } tanx = 0\\\\ \text{ Therefore:}\\ \lim_{x \to \pi } f(x) = dne \text{ (Does not exist})$

5 0

3 years ago

PLEASE ANSWER MY LATEST QUESTION PLEASE

siniylev [52]

Answer:

i will see if i can figure it out

gl dude

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers