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Margaret [11]
3 years ago
15

Express {x+1}{2x-3} as a trinomial.

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

2x^2 + 5x + 3

Step-by-step explanation:

First, expand the original equation:

(x + 1)(2x + 3)

2x^2 + 3x + 2x + 3

Now simplify:

2x^2 + 5x + 3

And that's your answer!

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Solve 3 + 4x > -5 for x
Debora [2.8K]

you have the following inequality:

3 + 4x > -5

in order to solve for x, proceed as follow:

3 + 4x > -5 subtract 3 both sides

4x > - 5 - 3

4x > -8 divide by 4 both sides

x > -8/4

x > -2

Hence, the solution to the given inequality is x > -2

7 0
1 year ago
If 3, x, y, -9 are in A.P, find the values of x and y.​
Serggg [28]

Answer:

  • x = -1
  • y = -5

Step-by-step explanation:

The common difference (d) can be found using the first and 4th terms:

  a1 = 3

  a4 = a1 +d(4 -1)

  -9 = 3 +3d . . . . . simplify

  -3 = 1 + d . . . . . . divide by 3

  -4 = d . . . . . . . . . subtract 1

Then ...

  x = a1 + d = 3 -4 = -1

  y = x + d = -1 -4 = -5

The values of x and y are -1 and -5, respectively.

6 0
3 years ago
Add. Write your answer in simplest form.
alexandr1967 [171]

Answer:

yes, you got it correct

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
16.
ss7ja [257]

The simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is 53 - w.

<h3>Linear equation:</h3>

Linear equation is an equation in which the highest power of the variable is equals to one.

Therefore, the number of economy-size cars rented in w weeks is represented as follows:

  • 152 + 3w

The number of full-size cars rented in w weeks is represented as follows:

  • 99 + 2w

where

w = number of weeks

A  simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is as follows:

  • 152 + 3w - (99 + 2w)
  • 152 + 3w - 99 - 2w
  • 53 - w

learn more on polynomial here: brainly.com/question/2566362

5 0
2 years ago
18. Which of the following is equivalent to √5p^2q×√5q?
faltersainse [42]
\sqrt{5p^{2}q } * \sqrt{5q} = p \sqrt{5q} * \sqrt{5q} = p( \sqrt{5q})^2 = \boxed{5pq}&#10;
3 0
3 years ago
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