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weeeeeb [17]
3 years ago
5

Solve for a. Please help!

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

a = 7

Step-by-step explanation:

This is a special trig triangles. Special trig triangles are identified by their angle measures and their sides have a unique relationship. This is a 30 - 60 - 90 triangle which has sides 1 - √3 - 2 or multiples of this. This means all 30 - 60 - 90 triangles have side lengths with the pattern 1 - √3 - 2. Here the triangle has a - 7√√3 - 14. The value of a is 7 since 7*√3 = 7√3 and 2*7 = 14.

You might be interested in
Which is the solution of the equation 1/4 ( 3x - 1 ) = 2x -2/3
Sever21 [200]

Answer:

x = 1/3 = 0.333

Step-by-step explanation:

Step  1  :

           2

Simplify   —

           3

Equation at the end of step  1  :

  1                       2

 (— • (3x - 1)) -  (2x -  —)  = 0

  4                       3

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

          2x     2x • 3

    2x =  ——  =  ——————

          1        3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 3 - (2)     6x - 2

————————————  =  ——————

     3             3  

Equation at the end of step  2  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  3  :

           1

Simplify   —

           4

Equation at the end of step  3  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  4  :

Equation at the end of step  4  :

 (3x - 1)    (6x - 2)

 ———————— -  ————————  = 0

    4           3    

Step  5  :

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  6x - 2  =   2 • (3x - 1)

Calculating the Least Common Multiple :

6.2    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       3

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

3 0 1 1

Product of all

Prime Factors  4 3 12

     Least Common Multiple:

     12

Calculating Multipliers :

6.3    Calculate multipliers for the two fraction

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 3

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

6.4      Rewrite the two fractions into equivalent fraction

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (3x-1) • 3

  ——————————————————  =   ——————————

        L.C.M                 12    

  R. Mult. • R. Num.      2 • (3x-1) • 4

  ——————————————————  =   ——————————————

        L.C.M                   12      

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(3x-1) • 3 - (2 • (3x-1) • 4)     5 - 15x

—————————————————————————————  =  ———————

             12                     12  

Step  7  :

Pulling out like terms :

7.1     Pull out like factors :

  5 - 15x  =   -5 • (3x - 1)

Equation at the end of step  7  :

 -5 • (3x - 1)

 —————————————  = 0

      12      

Step  8  :

When a fraction equals zero :

8.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -5•(3x-1)

 ————————— • 12 = 0 • 12

    12    

Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -5  •  (3x-1)  = 0

Equations which are never true :

8.2      Solve :    -5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

8.3      Solve  :    3x-1 = 0

Add  1  to both sides of the equation :

                     3x = 1

Divide both sides of the equation by 3:

                    x = 1/3 = 0.333

One solution was found :

                  x = 1/3 = 0.333

Processing ends successfully

plz mark me as brainliest :)

4 0
3 years ago
A parking garage charges $1.50 for the 1st hour of parking and $0.75 for each additional hour. What is the cost in dollars for p
QveST [7]
The equation you have to solve is 1.50 + (0.75 • 6). First, you solve what is in the parenthesis, 0.75 • 6 = 4.50. Now you simply add 1.50 and 4.50 to get $6, the total cost for 7 hours worth of parking. 
8 0
3 years ago
Help! Jeez these are hard.
Irina18 [472]

Answer:

option 2

Step-by-step explanation:

a colored in dot is less than or equal to or greater than or equal to while an uncolored dot is less then or greater than. arrow going left of the number is less than arrow going right is greater than. the problem is a is greater than 4/5 so an uncolored dot shout be on 4/5 going to the right

3 0
3 years ago
In the Salk vaccine field trial, 400,000 children were part of a randomized controlled double-blind experiment. Just about half
EastWind [94]

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

\hat p_1 = \dfrac{57}{200000}

=  0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

\hat p_2 = \dfrac{142}{200000}

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.  

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic  can be computed as:

Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}

Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}

Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}

Z = - 6.03

P-value =  2P(Z < -6.03)

From the Z - tables

P-value =  2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

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