If you borrow $200 for 12 years at
2 answers:
You might be interested in
So,
#1:
Convert to like improper fractions.
Add.
So, one solution could be
.
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2:
Convert into improper fraction form.
Multiply.
Cross-cancel, and we have our final result.
k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
#1:
Convert to like improper fractions.
Add.
So, one solution could be
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2:
Convert into improper fraction form.
Multiply.
Cross-cancel, and we have our final result.
k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
Let the legs of the triangle be a and b, and the hypotenuse c.
Your first instinct might tell you to use the Pythagorean theorem to go about solving this because
. This works, but it is slow.
The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.
Your first instinct might tell you to use the Pythagorean theorem to go about solving this because
The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.