The specific heat in, J /g °C of copper is 0.386J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:
- The specific capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
∆T = change in temperature (°C)
c = specific heat capacity (J/g°C)
For a colorimeter, the following equation applies:
m.c.∆T (water) = - m.c.∆T (metal)
m = 50g
c = 4.184 J/g°C
∆T = 29.2 - 26°C = 3.2°C
m = 70g
c = ?
∆T = 29.2 - 54°C = -24.8°C
m.c.∆T (water) = - m.c.∆T (metal)
50 × 4.184 × 3.2 = -(70 × c × -24.8)
669.44 = 1736c
c = 669.44 ÷ 1736
c = 0.386J/g°C
Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C
Learn more at: brainly.com/question/16787162?referrer=searchResults
POH will be -log[conc of OH]
-log (3.9E-08) = 7.409
pH = 14- pOH
pH = 14 - 7.409
pH = 6.59
Answer:
1.58gcm⁻³
Explanation:
Given parameters:
Volume of sample = 1.00L
Mass of sample = 1.58kg
unknown:
Density of the sample
Solution:
The density of a substance is expressed as its mass per unit volume.
The units of the parameters are given for volume as liters and for mass as kg.
We need to convert to cm³ for volume and into g for the mass:
1L = 1000cm³:
Therefore, the volume of the sample is 1000cm³
For the mass:
1kg = 1000g
1.58kg gives 1.58 x 1000g = 1580g
The density of the sample will be:
Density = 
Density = 
= 1.58gcm⁻³
Answer:
0.005712
Explanation:
5.712 grams = 0.005712 kilograms
H2O is the correct answer :)
