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sergey [27]
3 years ago
12

(this is a rhombus btw) for what value of x is the figure the given special parallelogram? HELP PLS, show work.

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0

Answer:

x = 2 or 3

Step-by-step explanation:

Diagonal of a rhombus bisects the vertex angles. So,

x^{2} =5x-6

=> x^{2} -5x + 6 = 0

Lets factorise the eqn.

=> x^{2} - 2x - 3x + 6 = 0

=> x (x - 2) -3(x-2)

=> (x-2)(x-3) = 0

Here x will have 2 values.

1) x-2=0

=> x =2

2) x - 3 = 0

=> x = 3

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