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Cerrena [4.2K]
3 years ago
7

On the line that passes through point C, mark a point D that is distinct from point C. Use the slope formula along with coordina

tes of points to find the slopes of and . Show your work.
Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

PLATO

Step-by-step explanation:

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Juliet opened a savings account at a bank by depositing $75. The account earns simple interest at a rate of 4% per year. The mon
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The money has been in the account f<span>or 5 years. This means that the amount of deposit was increased for 5 times. 
75*1.04*1.04*1.04*1.04</span>*1.04=75*1.04^5≈91.3 $
In this way i prefer to chose <span>D) $90.00 beacuse it's the nearest number</span>
4 0
3 years ago
A class of 33 students elected a class treasurer. there were 111votes for candidate a and 15 votes for candidate
Advocard [28]

Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be

11/33 x 100=33.333333...

About 33.333 of the voters voted for candidate a.

3 0
3 years ago
Write an integer that represents 5 inches of snow melting. *
miss Akunina [59]

Answer:

-5

Step-by-step explanation:

There was five inches of snow, correct? Now, the five inches are melting. It's kinda like subtraction.

5 - 5

6 0
4 years ago
Point 6 is on line segment FH. Given FG=8 and GH=11, determine length FH
Pie

Answer:

GH = 20

Step-by-step explanation:

We have that

FH = FG + GH ← substitute values

4x + 8 = x + 5x

4x + 8 = 6x ( subtract 4x from both sides )

8 = 2x ( divide both sides by 2 )

4 = x

Hence GH = 5x = 5 × 4 = 20GH = 20

7 0
3 years ago
The picture. and answer 1-6. please hurry
satela [25.4K]

Answer:

Step-by-step explanation:

From the figure attached,

1). Sin(D) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

2). Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

                = \frac{ED}{DF}

                = \frac{10}{26}

                = \frac{5}{13}

3). tan(D) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{EF}{DE}

               = \frac{24}{10}

               = \frac{12}{5}

4). sin(F) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

              = \frac{DE}{DF}

              = \frac{10}{26}

              = \frac{5}{13}

5). cos(F) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

               = \frac{EF}{DF}

               = \frac{24}{26}

               = \frac{12}{13}

6). tan(F) = \frac{\text{Adjacent side}}{\text{Adjacent side}}

               = \frac{DE}{EF}

               = \frac{10}{24}

               = \frac{5}{12}

4 0
3 years ago
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