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DENIUS [597]
2 years ago
7

Graph the description of each line A line has a slope of -3 and a y-intercept of 3.

Mathematics
2 answers:
Basile [38]2 years ago
5 0

Answer:

The equation is y = -3 + 3

Step-by-step explanation:

It will go through (0,3) and it wil go up 3 right one.

choli [55]2 years ago
4 0

Answer:

equation: y= -3x+3

Step-by-step explanation:

Subustitute formula y=mx+b for the slope=m and in this case the slope is -3. and the y intercept=b so if u plug in m and b in the formula y=mx+b you get y=-3x+3. next, since the slope, put the -3 over 1 to create a fraction. next, plot the point (0,3) as the y-int. then follow the pattern -3 down right 1. So the points to plot are (0,3), (1,0) (2,-3)  

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Assume the rate of inflation is 5​% per year for the next 2 years. What will be the cost of goods 2 years from​ now, adjusted fo
kirza4 [7]
The equation for inflation is
A = P*(1+r)^t
which is an exponential growth equation (if r > 0). If r < 0, then we have deflation.

where...
A = final price after t years
P = initial starting price
r = rate of inflation in decimal form 
t = number of years

In this case, 
A = unknown (we're solving for this)
P = 280 is the starting price
r = 0.05 is the decimal form of 5%
t = 2 years

We will plug these three pieces of info into the formula to get...
A = P*(1+r)^t
A = 280*(1+0.05)^2
A = 280*(1.05)^2
A = 280*(1.1025)
A = 308.70

Answer: 308.70 dollars
7 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
What is the shape of the cross section taken perpendicular to the base of a cylinder?
Fofino [41]
I believe the correct answer is RECTANGLE        
6 0
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Leya [2.2K]

Answer:

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r = 150.72/6.28

r = 24cm

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Answer:

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Step-by-step explanation:

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