<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
.875 seconds
a=360t
b=280t+(280*.25)
360t=280t+(280*.25)
360t=280t+70
80t=70
t=.875
The answer would be 4 as it more than 40 degrees whoch will allow to it record
Answer:
is there supposed to be a image there for us to see or no?
This would mean that the ratio is 2:1 or 2 to 1 or also 2/1.
The ratio would be that because it's 2 centimeters per 1 kilometer.
