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PolarNik [594]
3 years ago
14

Which of the following is equal to this expression? (256⋅64)^1/4

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:8•4 √4

Step-by-step explanation:

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H+20=35-4h please help
andrew-mc [135]
H+20=35-4H
first, combine your like terms, which are the Hs
add the 4H to both sides, and you will get
5H+20=35
now subtract 20 from both sides, that will cancel out the 20 on the left and leave you with 
5H=15
finally, divide both sides by 5 and you will get H=3.

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4 years ago
You and your 3 bothers want to share 5 candy bars describe how much of candy bars will they get
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They will get 1 1/4 of a candy bar
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3 years ago
Nickel-63 is a radioactive substance with a half-life of about 100 years. An artifact had
Marina CMI [18]

Answer:

see below

Step-by-step explanation:

The equation for half life is

n = no  e ^ (-kt)

Where no is the initial amount of a substance , k is the constant of decay and t is the time

no = 9.8

1/2 of that amount is 4.9 so n = 4.9 and t = 100 years

4.9 = 9.8 e^ (-k 100)

Divide each side by 9.8

1/2 = e ^ -100k

Take the natural log of each side

ln(1/2) = ln(e^(-100k))

ln(1/2) = -100k

Divide each side by -100

-ln(.5)/100 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/100 t)

Approximating ln(.5)/100 =-.006931472

n = 9.8 e^(-.006931472 t)  when t is in years

Now changing to days

100 years = 100*365 days/year

36500 days

Substituting this in for t

4.9 = 9.8 e^ (-k 36500)

Take the natural log of each side

ln(1/2) = ln(e^(-36500k))

ln(1/2) = -36500k

Divide each side by -100

-ln(.5)/36500 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/36500 d)

Approximating ln(.5)/365=-.00001899

n = 9.8 e^(-.00001899 d)  when d is in days

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3 years ago
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Multiply those 2 numbers and divide that answer by 2
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3 years ago
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