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2 years ago

5

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1 answer:

Juli2301 [7.4K]2 years ago

3 0

Answer:

81m2

Step-by-step explanation:

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One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago

Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system.

lbvjy [14]

Answer:

Your answer is B

Step-by-step explanation:

6.14 Checkpoint: Systems of Linear Inequalities

I took the test.

3 0

1 year ago

4/9 - 2/5 give answer in its simpliest form

wlad13 [49]

Answer:

2/45 is your answer

8 0

2 years ago

Evaluate (2-3) (4) - 9 -3.<br> -7<br> I<br> 11<br> 4

Delicious77 [7]

Answer:

-16

Step-by-step explanation:

8 0

3 years ago

Use the table to write a liner function that relates to y to x X: -2, 0, 2, 4

Contact [7]

I think this is the answer
(-2,5)
(0,4)
(2,3)
(4,2)

8 0

2 years ago