The sum of 3 fifteens and 4 twos will be 45 +8 = 53
Area = l x w
Area =9 x 4.25
A = 48.25
A≈ 48 in²
The length of that semi circle is 6pi. So the perimeter should be 6pi + 24
<h2>
Answer: -1.469</h2>
This trigonometric function can be written as:
(1)
Firstly, we have to solve the inner parenthesis:
(2)
Substituting (2) in (1):
(4)
Finally we obtain the value: