Answer:
1.is the answer:)............
I'm assuming the integral is

We have

Then substituting
and
, the integral transforms and reduces to

which we can rewrite as

and so

Answer:
The final simplification is (32p^-15).
Step-by-step explanation:
Given:
(2p^-3)^5 we have to simplify.
Property to be used:(Power rule)
Power rule states that:
...the exponents were multiplied.
Using power rule.
We have,
⇒
⇒
...taking exponents individually.
⇒
...
⇒
So our final values are 32p^-15
What is the size of trapezoid?