Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have
This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16
Complete the square
Rewrite as perfect squares
The vertex is the point
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0
square root both sides
the positive value is
As a decimal 4/15 = 0.2666667
As a decimal 3/10 = 0.3 [talk about close]
3/10 is bigger.
You could take an average to find something between 4/15 and 3/10
1/2(4/15 + 2/10)
1/2(8/30 + 6/30)
1/2(14/30)
1/2(7/15)
7/30 is between the two given numbers..
Answer:
9 square root of 2 or 12.73
So theres 366 days in a leap year,
you need to find hours, minutes, and then seconds
366 x 24 = 8,784 hours
8,784 x 60 = 527,040 minutes
527,040 x 60 = 31,622,400 seconds
31,622,400 seconds x 186,182 mps = 5.88 x 10^10
therefore light travels 5.88 x 10^10 in one leap year
Answer:
z=40 degrees
x=90 degrees
y=40 degrees
Step-by-step explanation:
To solve z you know that 50+90+z= 180 degrees. So z equals 40. To solve x you subtract 90 from 180 to get 90 degrees. To solve you add 50+x+y. You know that x= 90. You would add the angles together to get 180 degrees. 50+90=140 and 180-140 equals 40. Sorry if i'm wrong.