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3 years ago

Who answers this correctly with (explanation) gets vevmo'd/pay pal $40.

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

I think its 120 degree clockwise about point A and keep your money.

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Sela has 6 times as many coins as she had 4 months ago. If sela has 240 coins now ,How many coins did she have 4 months ago.

saw5 [17]

She has 40 coins since 40 times 6 is 240.

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3 years ago

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Graph y+6=4/5(x+3) using the point and slope given in the equation

Elodia [21]

Slope is 4/5
Points are (3,6)

Your first point should be (3,6) then from that point go up 4 and 5 to the right, that should be your second point, then graph.

6 0

4 years ago

Read 2 more answers

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

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3 years ago

DIRECTIONS: Use this information to answer Parts A and B.

asambeis [7]

Answer:

4630/130=35.6 so just round to 36 with a remainder of a few shirts

Step-by-step explanation:

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3 years ago

The professor of a large probability class randomly selected 8 students and asked the amount of time (in hours) spent for her co

Alekssandra [29.7K]

Answer:a. μ = 9.667 hours

b. σ = 1.972 hours

c. SE = 0.805 hour

Sample size (n) = 6

Sample data (xi) = 10, 8, 9, 7, 11, 13

a. Mean time spent in a week for this course by students:

Sample mean is given by:

Mean time spent in a week per student is 9.667 hours

b. Standard deviation of the time spent in a week for this course by students:

Standard deviation is given by:

c. Standard error of the estimated mean time spent in a week for this course by students:

Standard error is given by:

6 0

3 years ago