Answer:
.25 .75
.44 .56
Step-by-step explanation:
To find the relative frequency, we take the part over the total.
Since this is a relative frequency table, the total for each row is 1
Group 1 A = 15/ (15+45) = 15/60 = .25
Group 1 B = 45/(15+45) = 45/60 = .75
Group 2 A = 20 /(20+25) = 20/45 =.44
Group 2B = 25/(20+25) = 25/45 =.56
Answer:
- first mechanic: $105/hour
- second mechanic: $55/hour
Step-by-step explanation:
Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...
20r +5(160-r) = 2375
15r +800 = 2375 . . . . . . eliminate parentheses
15r = 1575 . . . . . . . . . . . . subtract 800
r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.
160-r = 55 . . . . . Second mechanic's rate
The first mechanic charged $105 per hour; the second, $55 per hour.
B - 4 where B is the variable representing the Bulls score
Answer:
ok thx
Step-by-step explanation:
Step-by-step explanation:
Just sum the number of cows and buffaloes:
2p^2 - p + 4 + p^2 + p + 1 = 3p^2 +5 animals.
