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Nezavi [6.7K]
3 years ago
8

The diagram represents liquid water in a pan on a hot plate. The liquid water is boiling and changing into water vapor. The proc

ess of boiling water is considered to be a
Chemistry
1 answer:
Alika [10]3 years ago
5 0

Answer:

Physical change

Explanation:

The molecules are being rearranged as the water changes phases from liquid to gas, but this doesn't change the chemical structure of the water.

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What is the sum of the coefficients needed to balance the combustion reaction of methane?
pishuonlain [190]

Answer:  The sum of the coefficients needed to balance the combustion reaction of methane is 6.

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The chemical equation for combustion of methane will be :

CH_4+2O_2\rightarrow CO_2+2H_2O

The coefficient foer methane is 1 , 2 for oxygen , 1 for carbon dioxide and 2 for water. The sum is 6.

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Which agent of erosion can create a limestone cave?
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Explanation:

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What are two main purposes for using repetition when conducting experiments <br> irements
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How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th
oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , n=\dfrac{2.666}{16}=0.167\ mole .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , m=12\times 0.167=2\ g .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

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3 years ago
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