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irina1246 [14]
4 years ago
13

An instrument used to separate cell parts according to density is the

Chemistry
1 answer:
grigory [225]4 years ago
7 0
It’s a centrifuger there are many steps to this do I advise looking on the internet or i could explain if needed
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What's an extensive property of matter
aev [14]

Answer:

Mass, Volume, Length, Moles, Energy, Number of Particles

Explanation:

8 0
4 years ago
Read 2 more answers
A system is composed of 7.14 grams of Ne gas at 298 K and 1 atm. When 2025 joules of heat are added to the system at constant pr
dlinn [17]

Answer:

(a) 1 atm, 8.72 L and 298 K respectively.

(b) 1 atm, 16.72 L and 573.35 K respectively.

(c) \Delta U=1215J

Explanation:

Hello,

(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{7.14g*\frac{1mol}{20g}0.082\frac{atm*L}{mol*K}*298K}{1atm}\\  \\V=8.72L

Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.

(b) Since the process was carried out at constant pressure, the work is defined as:

W=P(V_2-V_1)

Thus, the final volume is:

V_2=\frac{W}{P} +V_1=\frac{810Pa*m^3}{1atm*\frac{101325Pa}{1atm} } *\frac{1000L}{1m^3}+8.72L\\ \\V_2=16.72L

And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:

Q=mCp(T_2-T_1)\\\\T_2=\frac{Q}{mCp}+T_1 =\frac{2025J}{7.14g*1.03J/(g*K)}+298K\\ \\T_2=573.35K

Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.

(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:

Q-W=\Delta U\\\\\Delta U=2025J-810J\\\\\Delta U=1215J

Best regards.

8 0
3 years ago
A 1.5-m 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa. Now paddle-wheel work is done on the system until t
Assoli18 [71]

Answer:

The entropy change of carbon dioxide = 0.719 kJ/k

Explanation:

Given:

1.5 m - 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa

The objective is to determine the entropy change of carbon dioxide

Formula used:

ΔS=

Solution:

On considering,

C_{P} =0.846 kJ/kg K\\C_V=0.657 kJ/kg k\\

ΔS=mc_{v} lu\frac{p_{2} }{P_{1} }

On substituting the values,

ΔS=2.7*0.657lu\frac{150}{100}

ΔS=0.719 kJ/k

4 0
3 years ago
In 25 words or fewer, what do you think a scientist would want to explain about this soda?
Gnesinka [82]

Answer:

This soda is brown, sweet, has high carbonation, and is about 200 calories when consumed.

Explanation:

:)

8 0
3 years ago
What are the basis of making symbols????​
telo118 [61]

Answer:

1/ Using the first letter of the name of the elements.

2/  If the name of two or more elements begins with the same letter,the second letter of their name is also taken with first letter.

3/ Symbols are made by using the letters of the name of elements in other languages also.

4 0
4 years ago
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