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Phoenix [80]
3 years ago
9

What is the value of -16?

Mathematics
2 answers:
timama [110]3 years ago
5 0

Answer:

the answer would be -4

Step-by-step explanation:

Sindrei [870]3 years ago
4 0
The answer could be -4
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3 years ago
Solve the inequality for x. Show each step of the solution.<br> 4x-6(x+1)&gt;12
VLD [36.1K]
Answer:

x < - 9

steps:

4x - 6(x + 1) > 12

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8 0
3 years ago
in 4 minutes Liaa can type 140 words. If she has an essay taht is 700 words long , about how long will it take Liana to type it
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6 0
2 years ago
Need help please help me
ANTONII [103]
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
3 0
3 years ago
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