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Korvikt [17]
3 years ago
5

Find 345 x 6 using expanded form. 300+40+5=345

Mathematics
1 answer:
sweet [91]3 years ago
8 0

Answer:

2,000 + 0 + 70 + 0 = 2,070

Step-by-step explanation:

300 + 40 +5 x 6

300 + 4 = 340

340 + 5 = 345

345 x 6 = 2070

2,000 + 0 + 70 + 0 =

2,070

Hope this helps

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Rearrange the equation so uuu is the independent variable.<br> -12u+13=8w-3
Sunny_sXe [5.5K]

Step-by-step explanation:

- 12u + 13 = 8w - 3 \\  - 12u + 13 + 3 = 8w  \\  - 12u + 16 = 8w  \\ w =  \frac{ - 12u + 16}{8}   \\ w =  \frac{ - 3}{2} u + 2

I hope that is useful for you :)

4 0
3 years ago
Write the slope intercept form of the equation of each line
Sphinxa [80]

Answer:

Y = -1/2x+4

Step-by-step explanation:

The Y intercept is 4, so that's where the +4 comes in.

The slope is rise over run, so you count how many up you go from a whole number, in this case one, and that goes on top. Then you count how many it goes over, in this case two, and that goes on the bottom. The negative comes from which way the slope is going; down or up.

3 0
3 years ago
Read 2 more answers
The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s
lys-0071 [83]

Answer:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

IQR = Q_3 -Q_1 = 250-210 =40

For this case we need to find the lower and upper limit with the following formulas:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0
4 years ago
Which of the following is another way to express this equation. Queastion in picture. Giving brainliest
svlad2 [7]

Answer:

8+d=43

Step-by-step explanation:

answer is above

8 0
3 years ago
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Alex is making a rectangular garden and wants a fence around it. He wants the length of the garden to be 3 feet longer than the
givi [52]
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5 0
3 years ago
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