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1 answer:
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The answer is: 
.
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Explanation:
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We have: " 6⁻¹ * (-2)³ * (-4)⁻² = ? " ;
_______________________________________
Note: "6⁻¹ =
= 
" .
Note the following property of exponents:
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a⁻ˣ =
; {x ≠ 0}.
____________________________________________
Note: (-2)³ = (-2)*(-2)*(-2) = 4*(-2) = -8 .
_______________________________________
Note: (-4)⁻² =
;
=
;
=
;
____________________________________
So; we have:
_____________________________________
6⁻¹ * (-2)³ * (-4)⁻² ;
=
;
→ Cancel out the "8" in the "numerator" (to a "1") ; and the "16" in the number (and change to a "2"); since: {"16÷8 = 2" ; and since: "{8÷8=1"} ;
→and we have:
;
= .
_____________________________________
→ The answer is: .
_____________________________________
____________________________________________
Explanation:
____________________________________________
We have: " 6⁻¹ * (-2)³ * (-4)⁻² = ? " ;
_______________________________________
Note: "6⁻¹ =
Note the following property of exponents:
____________________________________
a⁻ˣ =
____________________________________________
Note: (-2)³ = (-2)*(-2)*(-2) = 4*(-2) = -8 .
_______________________________________
Note: (-4)⁻² =
=
=
____________________________________
So; we have:
_____________________________________
6⁻¹ * (-2)³ * (-4)⁻² ;
=
→ Cancel out the "8" in the "numerator" (to a "1") ; and the "16" in the number (and change to a "2"); since: {"16÷8 = 2" ; and since: "{8÷8=1"} ;
→and we have:
=
_____________________________________
→ The answer is:
_____________________________________
Answer:
Step-by-step explanation:
Hello!
You have the 95% CI for the mean [50; 70]
The amplitude for this interval is a= 20 and its margin of error is d= 10.
If the interval was constructed as X[bar] ± margin of error
Where the margin of error is the product of the statistic value due to the standard deviation of the distribution.
If you reduce the confidence level, the value of the statistic will be also reduced, so you would expect a shorter margin of error and amplitude for the 90% CI
Symbolically: d= * (δ/√n) ⇒ d↓=
↓ * (δ/√n) if d↓ ⇒ a↓
50 to 100 has an a= 50 and d= 25
70 to 90 has an a= 20 and d= 10
60 to 80 has an a= 20 and d= 10
55 to 95 has an a= 40 and d= 20
65 to 85 has an a=20 and d= 10
None of the given intervals corresponds to a 90% interval for the same sample as the first interval 50 to 70.
Another detail to keep in mind is that the intervals for the population mean are centered in the sample mean. From the first interval you can deduce that it is centered in X[bar]= 60 (Upper bond - margin of error = sample mean), if the other intervals were constructed with the same sample values, they should all be centered in 60.
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