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Vinil7 [7]
3 years ago
5

What is the slope, point, x-intercept, and y-intercept?

Mathematics
2 answers:
IceJOKER [234]3 years ago
5 0
X-int =(-3,0)
Y-int=(0,_1)
Slope: _1/3
SIZIF [17.4K]3 years ago
4 0
As for the slope, it is the deviation of the line from a horizontal. Slope is expressed as \frac{change in y}/{change in x}.
A point is any point on the coordinate plane. Points are expressed as an ordered pair in the form (x,y). Examples include (5,) and (2,1).
The x-intercept of a line is the point at which it intercepts, or intersects, the x-axis. In other words, it is the point where the line crosses the x-axis.
The y-intercept of a line is the point where it intercepts the y-axis.
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Solve the linear inequality -4x<16
Elanso [62]
We have to divide both sides by -4 to get x by itself and solve the inequality

-4x∠16
----   ---
-4      -4

x∠-4

thats your final answer
8 0
4 years ago
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What is the perimeter in square units of the rectangle shown on the coordinate grid?
Rashid [163]

In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

\bigstar\;\; \mathsf{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

There are two lengths in a rectangle. Let us find any one length of the rectangle.

I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)

Here :  x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10

Substituting the values in the distance formula, We get :

\mathsf{\implies Length = \sqrt{[-2 - (-8)]^2 + [10 - 2]^2}}

\mathsf{\implies Length = \sqrt{[-2 + 8]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{[6]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{36 + 64}}

\mathsf{\implies Length = \sqrt{100}}

\mathsf{\implies Length = 10}

There are two widths in a rectangle. Let us find any one width of the rectangle.

I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)

Here :  x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7

Substituting the values in the distance formula, We get :

\mathsf{\implies Width = \sqrt{[2 - (-2)]^2 + [7 - 10]^2}}

\mathsf{\implies Width = \sqrt{[2 + 2]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{[4]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{16 + 9}}

\mathsf{\implies Width = \sqrt{25}}

\mathsf{\implies Width = 5}

Perimeter of a Rectangle is given by : 2[Length + Width]

:\implies  Perimeter of the given rectangle = 2[10 + 5]

:\implies  Perimeter of the given rectangle = 2[15]

:\implies  Perimeter of the given rectangle = 30

<u>Answer</u> : Perimeter of the given rectangle is 30 square units

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3 years ago
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Amiraneli [1.4K]

Answer:

3n + 7 + n and 4n + 7

Step-by-step explanation:

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