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3 years ago

Solve: 13/19 - (-1/19) A. -12/19 B. -14/19 C. 14/19 D. 12/19

Mathematics

2 answers:

wel3 years ago

7 0

Answer:

Step-by-step explanation:Any time you have a subtraction and a negitive right next to eachother, it means to add. So, you would add 13 and 1 to get 14, then keep the denominator 19 to get 14/19.

yarga [219]3 years ago

3 0

Answer:

c.14/19

Step-by-step explanation:

because math exists

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What is the range of the function f(x) = -|X - 4| + 5?

Law Incorporation [45]

Answer:

Range = (-∞, 5)

Step-by-step explanation:

This is the absolute value function with transformation.

The parent function is f(x) = |x|

This function has a "negative" in front, so it makes it reflect about x axis

The -4 after x makes horizontal translation of 4 units right

the +5 at the end makes the function translate 5 units UP

The graph is shown in the attached picture.

Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the range is -infinity to 5

answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5

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4 years ago

Joel earns 1500 per month. if he spends 375 on rent each month what percent of his income does he has

Harman [31]

He still has 75% of his income left because 1500/375=4 so he spent 1/4 of his check and has 3/4 left.

8 0

3 years ago

Read 2 more answers

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

What are the next three terms in the sequence?

Ne4ueva [31]

-1 + 10 = 9 +10 = 19 + 10 = 29 so the next would be 39 because you add ten to it and there is only one answer with 39 so it's C

7 0

4 years ago

Read 2 more answers

Use the figure at the right to answer the following questions.

Lisa [10]

<h3>Answers:</h3>

1. Name all the line segments.

Ans.  PL, LA, AY, YS,

2. How many line segments were formed?

Ans.  4 (four)

3. Name all rays

Ans. AM, AN

4. How many rays were formed?

Ans. 2 (two)

5. Name the opposite rays :

Ans. AM, AN

6. Is point A between MN ?

Ans. Yes

7. Find the line segments and rays formed by 5 points.

Ans. 

Line segment = PL, LA, AY, YS,
Rays = AM, AN

<h3>Hope it helps you.</h3>

7 0

2 years ago