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Anastaziya [24]
3 years ago
10

The greatestcommonfactor of 8, 52

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0
The GCF is the largest number that both will divide into. Eight is the larger of the two, but 52 is not divisible by 8. The next highest value is 4. 8÷4=2 and 52÷4=13. Therefore, the GCF is 4.
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Find an equation of the tangent plane to the given parametric surface at the specified point.
Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}

Step-by-step explanation:

Given equation

      r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}---(1)

Normal vector  tangent to plane is:

\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}

\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}

Normal vector  tangent to plane is given by:

r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]

Expanding with first row

\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\

at u=5, v =π/3

                  =\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k} ---(2)

at u=5, v =π/3 (1) becomes,

                 r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}

                r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}

                r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}

From above eq coordinates of r₀ can be found as:

            r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})

From (2) coordinates of normal vector can be found as

            n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)  

Equation of tangent line can be found as:

  (\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}

5 0
3 years ago
Find the coordinates of the midpoint of each segment and find the length of each segment
Tasya [4]

Answer:

Is this the whole question or u cut it?

3 0
3 years ago
-GEOMETRY PROBLEM- I don’t understand this problem, can anybody help? The question is in the picture. Thanks! I’ll give 15 point
svetoff [14.1K]
In tue picture, we can see 2 triangles and they already labeled 2 congruent sides. We also see that the line in the middle is being shared between the 2 triangles, making the side equal. Using the SSS theorem, we can prove that these teiangles are congruent to each other. Hope this helps.
3 0
3 years ago
Does anyone know how to do this problem? Thanks.
svet-max [94.6K]
See picture for answer

8 0
3 years ago
HELP ASAP!!! ILL GIVE BRAINLY TO THE ONE THAT ACTUALLY HELPS ME!!!! PLEASE ASAP HELP NO JOKING! PLUS THERE IS 50 POINTS TO THE B
ella [17]

The random nature of the process is why Gina doesn't get the theoretical probability. If she were to repeat this experiment say 1000 or perhaps 10,000 times, then her experimental probability value should get closer to 1/2. It likely won't land *exactly* on 1/2 because again of the random nature of the outcomes.

For more information, check out the Law of Large Numbers.

7 0
2 years ago
Read 2 more answers
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