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3 years ago

Which ratio is equal to 78?

Mathematics

1 answer:

lyudmila [28]3 years ago

5 0

Answer:

78 : 162 = 13 : 27. These two equalities are examples of proportions (equal ratios); it is as simple as that.

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Please check my answer : Find the equation of the line that has a slope of 8 and passes through the point (-3,4). I got y=8x-20

Paladinen [302]

The answer is y = -8x - 20. If you were to use y = 8x - 20 then you'd get 4 = -44, which, obviously, is not true. To fix it all you need to do is add a negative sign in front of the 8. y = -8x - 20.

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3 years ago

The estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is

mixas84 [53]

Answer: The equation that represents the give situation is, y = 0.75 x + 12

Step-by-step explanation:

Here, x represents the number of batteries the child bought and y represents the total cost.

Since, the cost of one batteries = $ 0.75

⇒ The cost of x batteries = 0.75 x

The cost of one toy = $ 12

Hence, the total cost = The cost of one toy + The cost of x batteries

= y = 0.75 x + 12

Which is the required equation that represents the given situation.

6 0

3 years ago

Read 2 more answers

The first term in a sequence is 5. Each new term in the sequence is obtained by adding 4 to the previous term. Determine an equi

ycow [4]

Answer:

4x+1

Step-by-step explanation:

3 0

3 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

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4 years ago

Find the average of 2, 6, 12, 8, and 7

Crazy boy [7]

Answer:

Step-by-step explanation:

7 0

3 years ago