Sum of n terms of a geometric series is
Sn = a1 (r^n-1)/(r-1)
a1 = 1st term = 4
r = common ratio = 12/4 = 3
so, the sum is
Sn = 4 (3^n-1)/(3-1) = 2(3^n-1)
It’s reflected across the origin. Or to the right across the y axis. Then down across the x axis
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<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Answer:
24 and 15
Step-by-step explanation: