Please help with this!
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Answer:
Step-by-step explanation:
The rule is ...
log(a/b) = log(a) -log(b) . . . . all logs to the same base
Then for a/b = 13/x, this becomes ...
log(13/x) = log(13) -log(x)
If the base of logarithms is 9, then this is ...
log9(13/x) = log9(13) -log9(x)