The range is the largest number minus the smallest number
10-4
=6
so 6 is your range
^o^
Answer:
x ∈ {-a, -b}
Step-by-step explanation:
1/(a+b+x) = 1/a +1/b +1/x . . . . given
abx = bx(a+b+x) +ax(a+b+x) +ab(a+b+x) . . . . multiply by abx(a+b+x)
(a+b)x^2 +(a+b)^2x +ab(a+b) = 0 . . . . . subtract abx
x^2 + (a+b)x +ab = 0 . . . . . divide by (a+b)
This is a quadratic equation in x. It will have two solutions, as given by the quadratic formula.
x = (-(a+b) ±√((a+b)^2 -4(1)(ab))/(2(1)) = (-(a+b) ± |a -b|)/2
Without loss of generality, we can assume a ≥ b, so |a -b| ≥ 0. Then ...
x = (-a -b -a +b)/2 = -a
x = (-a -b +a -b)/2 = -b
There are two solutions: x ∈ {-a, -b}.
It's simple .....
just subtract R and C.....
so 50x+10-10x-275
= 40x-265
so the answer is B
Answer:
55 sq. in.
Step-by-step explanation:
Area of figure
= area of triangle + area of rectangle
height of triangle = 6 in.
base of triangle = 6/(sqrt(3)/3) = 18/sqrt(3)
Area of triangle = 6*18/sqrt(3) /2 = 54/sqrt(3) = 31.18 sq. in.
Area of rectangle = 6 * 4 = 24 sq. in
Area of figure = 31.18+24 = 55.18 sq. in
