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MissTica
4 years ago
8

Help please fast is important

Mathematics
2 answers:
vazorg [7]4 years ago
7 0

Answer:

can't see

Step-by-step explanation:

guapka [62]4 years ago
5 0

Answer:

i do not know

Step-by-step explanation:

 mmmmmmmmmmmmmmmmmmmm,,,,,

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The axis of symmetry of a parabola is x = 6, and one point on the parabola is (2,8). What is the mirror point for the point (2,8
seraphim [82]
As the symmetry of axis is x=6, the mirror point of (2,8) will be (10,8)
4 0
2 years ago
Plz help I’ll mark you
Anni [7]

Answer:

C. 6.8 in

Step-by-step explanation:

hope it helps please correct me If I am wrong

3 0
3 years ago
Simplify (–8q3r4s2)2 = ? <br> A. –64q9r16s4 <br> B. 64q6r8s4 <br> C. –64q6r8s4 <br> D. 64q9r16s4
Novay_Z [31]
-8q^2 = 64q
3r^2 = 9r
4s^2 = 16s
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total is 64q9r16s4
6 0
3 years ago
If K(-1, 2) is reflected over the x-axis, then the image is K'
musickatia [10]

Answer:

(K'(- 1, - 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

Thus

K(- 1, 2 ) → K'(- 1, - 2 )

6 0
4 years ago
Read 2 more answers
Find the 9th partial sum of the geometric sequence an=43n–1.
siniylev [52]

Answer:

39364.

Step-by-step explanation:

I guess its an = 4*(3)^(n-1)

r = 3, a1 = 4 and n = 9

Sum of n terms = a1 * (r^n - 1) / (r - 1)

so S9 = 4 *(3^9 - 1) / (3 - 1)

= 4 * (19683  - 1) / 2

= 78728/2

= 39364.

7 0
3 years ago
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