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Levart [38]
3 years ago
5

Factorise x^2-x-6 please help

Mathematics
2 answers:
Murljashka [212]3 years ago
5 0

Answer:

x^2-3x+2x-6=0

x(x-3)+ 2(x-3)=0

(x+2)(x-3)=0

x=3,-2

max2010maxim [7]3 years ago
3 0

Answer:

Ask: Which two numbers add up to -1 and multiply to -6

-3 and  

2. Rewrite the expression using the above.

(x-3)(x+2)

Step-by-step explanation:

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Compute the following.<br> f(40) − f(0)/40 − 0
Rudik [331]

Answer:

the slope of the tangent line at (40, f(40))the slope of the tangent line at (15, f(15)) the slope of the tangent line at (10, f(10))the slope of the line segment from (10, f(10)) to (40, f(40))

6 0
2 years ago
Find x when f(x)=1 . (These means find the input that gives an output of 1.)<br><br> f(x)=1/x-2
Andreyy89

Answer:

x = 1/3

Step-by-step explanation:

1 = 1/x -2

add 2 to both sides

3 = 1/x

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5 0
3 years ago
In a genetic experiment involving flower color in phlox, a ratio of 3 blue-flowered plants to 1 whiteflowered plant was expected
aliya0001 [1]

Answer: The observed ratio is different from the expected ratio.

Step-by-step explanation:

Since we have given that

Expected ratio :

Ratio of blue flowered plants to white flowered plant = 3:1

Observed results:

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Number of white flowered plants = 14

So, Ratio of blue flowered plants : white flowered plants

35:14\\\\=5:2

So, 5:2 ≠ 3:1

Hence, the observed ratio is different from the expected ratio.

3 0
3 years ago
Opposite reciprocal of -2/3? geometry/algebra
Ulleksa [173]
The answer would be -3/2

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When using this in fractions just switch the numerator and denominator. This is done by dividing the fraction by one, but in the case of a negative fraction you would divide by negative 1.
8 0
3 years ago
Identify the hyperbolas (represented by equations) whose centers are at (2, 1)
weqwewe [10]
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
5 0
3 years ago
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