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2 years ago

Can you Help me please

Mathematics

2 answers:

Novosadov [1.4K]2 years ago

8 0

Answer:

I have attached a picture of me solving the equation. If you have any questions I am here to help. Hope this helps, thank you :) !!

Evgen [1.6K]2 years ago

6 0

Answer:

-1

Step-by-step explanation:

mn = -3 because 3 × -1 = -3

p^2 = 4 because 2^2 = 4

Then 4 + -3 = -1

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A boy had a packet of 320 candies with 2 different flavours. 7/16 were orange flavour and the rest were lemon. He gave his frien

MrRa [10]

30 lemon candies he give his friend.

It is given that a boy had 320 candies. There were 2 flavors. 7/16 were orange flavor and the rest were lemon. He gave his friend 30 orange candies and some lemon ones.

320 (7/16) = 140 were orange

320 - 140 = 180 were lemon

Let x be the number of lemon ones he gave away

So,

[ 140 - 30 ] / [ 180 - x ] = 11/15

110 = (11/15) ( 180 - x )

(15/11) (110) = 180 - x

150 = 180 - x

x = 180 - 150 = 30

Learn more about word problems here: brainly.com/question/20521181

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6 0

1 year ago

The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0

2 years ago

Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.

NikAS [45]

Answer: These are some points of the grahp:

(-2,4)

(0, 3)

(2, 2)

Explanation:

1) f(x) = -0.5x + 3, is the equation of the form y = mx + b

2) y = mx + b is slope-intercept equation of a line where the slope is m and the y-intercept is b, so, f(x) = - 0.5x + b has slope m = -0.5 and y-intercept b = 3.

3) To graph f(x) = -0.5x + 3, follow these steps:

draw two perpedicular axis: vertical axis, labeled y, and horizontal axis, labeled x.
draw marks on each axis, each mark equivalent to one unit.
the intersection point of the vertical and horizontal axis is the origin, i.e. point (0,0).
you can make a table with two or more points:

x f(x) = - 0.5x + 3

-2 4

0 3

2 2

4 1

6 0

4) You can see the graph in the figure attached, and select any of the points on the line either by using the table or by using the equation f(x) = -0.5x + 3.