All categories

3 years ago

What is the length of EF ?

Mathematics

1 answer:

fgiga [73]3 years ago

4 0

Perimeter is the sum of all outside dimensions.

Solve for x first:

12 + x+7 + x+2 + 5 + x +4 + x + 4 = 42

Combine like terms:

4x + 34 = 42

Subtract 34 from both sides:

4x = 8

Divide both sides by 4:

X = 2

Now solve for EF by replacing x:

EF =. X + 7 = 2 + 7 = 9 feet.

You might be interested in

12% of ____ shirts is 36 shirts

MrMuchimi

12% of 300 shirts is 36 shirts

4 0

3 years ago

Read 2 more answers

n a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of inches and a stand

kotykmax [81]

Answer:

(a) The probability that a study participant has a height that is less than 67 inches is 0.4013.

(b) The probability that a study participant has a height that is between 67 and 71 inches is 0.5586.

(c) The probability that a study participant has a height that is more than 71 inches is 0.0401.

(d) The event in part (c) is an unusual event.

Step-by-step explanation:

The complete question is: In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of 67.5 inches and a standard deviation of 2.0 inches. A study participant is randomly selected. Complete parts (a) through (d) below. (a) Find the probability that a study participant has a height that is less than 67 inches. The probability that the study participant selected at random is less than inches tall is nothing. (Round to four decimal places as needed.) (b) Find the probability that a study participant has a height that is between 67 and 71 inches. The probability that the study participant selected at random is between and inches tall is nothing. (Round to four decimal places as needed.) (c) Find the probability that a study participant has a height that is more than 71 inches. The probability that the study participant selected at random is more than inches tall is nothing. (Round to four decimal places as needed.) (d) Identify any unusual events. Explain your reasoning. Choose the correct answer below.

We are given that the heights in the 20-29 age group were normally distributed, with a mean of 67.5 inches and a standard deviation of 2.0 inches.

Let X = the heights of men in the 20-29 age group

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean height = 67.5 inches

$\sigma$ = standard deviation = 2 inches

So, X ~ Normal( $\mu=67.5, \sigma^{2}=2^{2}$ )

(a) The probability that a study participant has a height that is less than 67 inches is given by = P(X < 67 inches)

P(X < 67 inches) = P( $\frac{X-\mu}{\sigma}$ < $\frac{67-67.5}{2}$ ) = P(Z < -0.25) = 1 - P(Z $\leq$ 0.25)

= 1 - 0.5987 = 0.4013

The above probability is calculated by looking at the value of x = 0.25 in the z table which has an area of 0.5987.

(b) The probability that a study participant has a height that is between 67 and 71 inches is given by = P(67 inches < X < 71 inches)

P(67 inches < X < 71 inches) = P(X < 71 inches) - P(X $\leq$ 67 inches)

P(X < 71 inches) = P( $\frac{X-\mu}{\sigma}$ < $\frac{71-67.5}{2}$ ) = P(Z < 1.75) = 0.9599

P(X $\leq$ 67 inches) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{67-67.5}{2}$ ) = P(Z $\leq$ -0.25) = 1 - P(Z < 0.25)

= 1 - 0.5987 = 0.4013

The above probability is calculated by looking at the value of x = 1.75 and x = 0.25 in the z table which has an area of 0.9599 and 0.5987 respectively.

Therefore, P(67 inches < X < 71 inches) = 0.9599 - 0.4013 = 0.5586.

(c) The probability that a study participant has a height that is more than 71 inches is given by = P(X > 71 inches)

P(X > 71 inches) = P( $\frac{X-\mu}{\sigma}$ > $\frac{71-67.5}{2}$ ) = P(Z > 1.75) = 1 - P(Z $\leq$ 1.75)

= 1 - 0.9599 = 0.0401

The above probability is calculated by looking at the value of x = 1.75 in the z table which has an area of 0.9599.

(d) The event in part (c) is an unusual event because the probability that a study participant has a height that is more than 71 inches is less than 0.05.

7 0

3 years ago

Ben and Susan are truck drivers who start at the same location. Ben drives 300 miles due west and Susan drives 160 miles due sou

Paul [167]

Answer:

Ben and Susan will be 340 miles apart

Step by Step Solution

Step 1: We plot the problem on a graph to visualize the problem

Step 2: We notice that the problem creates a right triangle with the distance Ben and Susan travel as the legs of the right triangle

Step 3: We can use the Pythagorean Theorem: a²+b²=c² to solve the distance between Ben and Susan

Step 4: We enter the numbers into the formula

a² + b² = c²

300² + 160² = c²

90000 + 25600 = c²

115600 = c² *square root both sides

c = 340

Therefore Ben and Susan are 340 miles apart

8 0

3 years ago

Unit rate of 357 miles In 6.3 hours

insens350 [35]

56.67 miles per hour

3 0

3 years ago

Read 2 more answers

Cat had 575 shirts on Monday. On Tuesday she gave away 125 shirts. Which equation represents a one-step equation?

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

im not 100% sure sorry

8 0

3 years ago

Read 2 more answers