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3 years ago

Find the zeros of the function by factoring 3x^2+ 10x=8

Mathematics

1 answer:

Wittaler [7]3 years ago

6 0

Answer:

$x=\frac{2}{3}, -4$

Step-by-step explanation:

hope this helps!

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Hi, can someone help explain this. (Triangle similarity/10th grade)

scZoUnD [109]

This is one proportion that can be created from the given information $\frac{36}{24} = \frac{6x-6}{3x+7}$ .

You would then use cross product to solve it. Also reduce 36/24 to 3/2
3(3x + 7) = 2(6x - 6)
9x + 21 = 12x - 12
33 = 3x I subtracted 9x from both sides and added 12 to both sides
11 = x

5 0

3 years ago

In a servey of 80 people ,it was found that 60 liked oranges only and 10 liked both oranges and apples.The nuber of people who l

I am Lyosha [343]

Answer:

10 people didn't answer the servey

Step-by-step explanation:

servey=80 people

70= answered the servey

so we should take the difference:-

80–70= 10

Hope I got the right answer!

4 0

3 years ago

I have two U.S. coins that total 30 cents. One is not a nickel. What are the two coins?

yaroslaw [1]

To solve the given problem, we need to know the types of US coins. The given problem is one of the tricky problems. So lets find out

In the united states, there are six types of coins produced. Penny- 1 cent, nickel- 5 cents, dime- 10 cents, quarter- 25 cents, half dollar- 50 cents and dollar- 100 cents. So u should know these types to slove this know lets move on to the :

Answer and Explanation:

The given problem is a kind of a riddle. It is given that the total of two US coins is

cents.

One is not a nickel, But the other one can be a nickel=

cents. So, the first one coin is a quarter=

cents. Which gives the total

cents.

Therefore, the two coins are a nickel and a quarter.

<h3> Hope you understood it!!!</h3>

4 0

3 years ago

An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$