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Paladinen [302]

3 years ago

9

Please help! I need this done!

1 answer:

amid [387]3 years ago

4 0

Answer:

2. c

3. c

4. cx

5. c(c-x)

6. cx

7. c(c-x)

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A hot air balloon is 910 feet above sea level. It is rising at a rate of 4 feet fee second. How high is the hot air balloon afte

nalin [4]

Answer:

1230

Step-by-step explanation:

80 x 4 = 320

320 + 910 = 1230

5 0

2 years ago

John had $21 to spend on 2 notebooks. After buying them he had $13. How much did each notebook cost?

Eva8 [605]

john had 21.00After buying 2 notebooks he had 13.00

21-13= 8 / 2 =4 each notebook cost 4 dollars.

5 0

3 years ago

find the coordinates of point Z that splits the segment XY located 3/7 of the way between X(-2,1) and Y(4,5)

Drupady [299]

Answer:

Z(-0.2, 2.2).

Step-by-step explanation:

We will use section formula when a point, say P, divides any segment ,say AB, internally in the ratio m:n.

$[x=\frac{mx_2+nx_1}{m+n}, y= \frac{my_2+ny_1}{m+n}]$

We have been given the points of segment XY as X at (-2,1) and Y at (4,5) and ratio is 3:7.

$(x_1, y_1)=(-2,1)$

$(x_2, y_2)=(4,5)$

$m:n=3:7$

Upon substituting coordinates of our given points in section formula we will get,

$[x=\frac{(3*4)+(7*-2)}{3+7}, y= \frac{3*5+7*1}{3+7}]$

$[x=\frac{12-14}{10}, y= \frac{15+7}{10}]$

$[x=\frac{-2}{10}, y= \frac{22}{10}]$

$[x=-0.2, y= 2.2]$

Therefore, coordinates of point Z will be (-0.2, 2.2).

7 0

3 years ago

1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat

brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

$x = 2$ is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) $f(x) = 6x + 6/x$

$f\prime(x) = 6 - 6/x^2 = 0$ and $x \neq 0$

So, the roots are $x = -1$ and $x = 1$

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

$x = -1$ is local maximum, $x = 1$ is local minimum.

2) $f(x)=6-4/x+2/x^2$

$f\prime(x)=4/x^2-4/x^3=0$ and $x \neq 0$

So the root is $x = 1$

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

$x = 1$ is absolute minimum.

3) $f(x) = 8x^2/(x-4)$

$f\prime(x) = (8x^2-64x)/(x-4)^2=0$ and $x \neq 4$

So the roots are $x = 0$ and $x = 8$

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

$x = 0$ is local maximum, $x = 8$ is local minimum.

4) $f(x)=6(x-2)^{2/3} +4=0$

$f\prime(x) = 4/(x-2)^{1/3}$ has no solution and $x = 2$ is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

$x = 2$ is absolute minimum.

5) $f(x)=8\sqrt x - 6x$ for $x>0$

$f\prime(x) = (4/\sqrt x)-6 = 0$

So the root is $x = 4/9$

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

$x = 0$ is local minimum, $x = 4/9$ is absolute maximum.

5 0

3 years ago

Vikki [24]

It is 60 times greater because 60 pennies=6 dimes . 6 dimes=60 pennies
Or
10 times greater because 6×10=60 60=6 dimes

8 0

3 years ago

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