I need help with this question

Mathematics

2 answers:

UNO [17]4 years ago

7 0

9514 1404 393

Answer:

11/20

Step-by-step explanation:

It is appropriate to "invert and multiply".

$\dfrac{5}{20}\div\dfrac{5}{11}=\dfrac{5}{20}\times\dfrac{11}{5}=\dfrac{5\times11}{5\times20}=\boxed{\dfrac{11}{20}}$

nata0808 [166]4 years ago

5 0

I don't know if you've learnt this, but there's something called the KFC rule (you use it when dividing fractions), so k basically stands for keep (so you keep the first fraction), f stands for flip (so you flip the second fraction) and c stand for change (you change the division sign to a multiplication sign)

So you get

5/20*11/5

55/100

which is 11/20

so, an answer of 11/20 would make Quintin correct

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CaHeK987 [17]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Please help! Correct answer only, please! Consider the matrix shown below: Find the determinant of the matrix Q. A. -67 B. -65 C

Nonamiya [84]

Answer: d) 67

<u>Step-by-step explanation:</u>

$determinant\ \left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&j\end{array}\right] = a\cdot det\left[\begin{array}{cc}e&f\\h&j\end{array}\right] -\ b\cdot det\left[\begin{array}{cc}d&f\\g&j\end{array}\right] +\ c\cdot det\left[\begin{array}{cc}d&e\\g&h\end{array}\right]$

$determinant\ \left[\begin{array}{ccc}2&3&4\\-3&2&1\\5&-1&6\end{array}\right] \\\\\\= 2\cdot det\left[\begin{array}{cc}2&1\\-1&6\end{array}\right] -\ 3\cdot det\left[\begin{array}{cc}-3&1\\5&6\end{array}\right] +\ 4\cdot det\left[\begin{array}{cc}-3&2\\5&-1\end{array}\right]\\\\\\=2[2(6)-1(-1)]-3[-3(6)-1(5)]+4[3(-1)-2(5)]\\\\\\=2(13)-3(-23)+4(-7)\\\\\\=26+69-28\\\\\\=\large\boxed{67}$