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babymother [125]
3 years ago
12

Find the output, k, when the input, t, is 3. K=13t-2 K=

Mathematics
1 answer:
zalisa [80]3 years ago
7 0
K=37

You multiply 13 and 3 and you get 39. You then subtract 2 from 39 to get K.
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Find the volume of a pyramid with a square base, where the side length of the base is 14.7 and the height of the pyramid is 17.2
Romashka-Z-Leto [24]

Answer: 1238.916

Step-by-step explanation:

A = (Bh)/3

B = 14.7 x 14.7

The area of a pyramid is the formula at the top. B in the formula at the top is the Base. The reason it is capitalized is because B is also a formula. You need to find the area of the base of the pyramid and plug it into the equation. It this case, the base is equal to the second equation above.

7 0
3 years ago
Parallel and perpendicular worksheet
vlada-n [284]

Answer:

i used to know how to do this but i forgot sorry hope someone helps

Step-by-step explanation:

Good Luck!!

5 0
3 years ago
If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction b
deff fn [24]

Answer:

B

Step-by-step explanation:

Assuming the denominator is 16 (to fit with the second part), 9+3 is 12 and 12/16 is 3/4.

If we take 7 from 16 we also get 9, which is thus 1.

4 0
4 years ago
At Ree Ski Center, the most people will pay for a neck warmer is $10. The manager of Ree Ski Center knows he needs a 30% markup
taurus [48]

Let x be the most the manager can pay the suppliers.

Then, we know from the information given in the question that the manager needs a 30% markup based on cost.

Therefore, the guiding equation will be:

x+\frac{30}{100}x\leq 10

because $10 is the most people will pay for a neck warmer.

Thus, the above equation will become:

x+0.3x\leq 10

1.3x\leq 10

x\leq \frac{10}{1.3}=7.69

\therefore x\leq 7.69

Thus, the most a manager can pay the suppliers for neck warmers and still keep the selling price at $10 is $7.69

4 0
4 years ago
PLEASE HELP ASAP! ITS URGENT! Thank you.
Arte-miy333 [17]

Let's plug in x = 2.

f(x) = x^2

f(2) = 2^2 ... replace every x with 2

f(2) = 4

----------

Now plug in x = 3.

f(x) = x^2

f(3) = 3^2 ... replace every x with 3

f(3) = 9

-----------

And x = 5 as well.

f(x) = x^2

f(5) = 5^2 .... replace every x with 5

f(5) = 25

-----------

We see that

f(2)+f(3) = 4+9 = 13

which is not equal to f(5) = 25.

So f(2)+f(3) = f(5) is false.

------------

Another way to phrase why it doesn't work is because (2,3,5) isn't a pythagorean triple. The equation 2^2+3^2 = 5^2 is false.

If it said f(3)+f(4) = f(5), then it would be correct because 3^2+4^2 = 5^2 is a true equation.

6 0
3 years ago
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