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3 years ago

Find the output, k, when the input, t, is 3. K=13t-2 K=

Mathematics

1 answer:

zalisa [80]3 years ago

7 0

K=37

You multiply 13 and 3 and you get 39. You then subtract 2 from 39 to get K.

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Help of using proportion to solve problems

Sindrei [870]

Hint: it will help to change all denominators to the same one using gcf or lcm

4 0

3 years ago

This is 6th grade math. How do you evaluate the following. The ^ is to represent that the number after is in the exponent positi

evablogger [386]

Answer:

Step-by-step explanation:

First, you description of ^ is very well written as well as being correct.

Second: all you can do is combine the 6 and 28. They are like terms

34 - c^3

That's as much of an answer as you can get.

5 0

2 years ago

A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly se

Darina [25.2K]

Answer: (17.42, 20.78)

Step-by-step explanation:

As per given , we have

Sample size : n= 9

$\overline{x}=19.1$ years

Population standard deviation is not given , so it follows t-distribution.

Sample standard deviation : s= 1.5 years

Confidence level : 99% or 0.99

Significance level : $\alpha= 1-0.99=0.01$

Degree of freedom : df= 8 (∵df =n-1)

Critical value : $t_c=t_{(\alpha/2,\ df)}=t_{0.005,\ 8}= 3.355$

The 99% confidence interval for the population mean would be :-

$\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}$

$19.1\pm (3.355)\dfrac{1.5}{\sqrt{ 9}}\\\\=19.1\pm1.6775\\\\=(19.1-1.6775,\ 19.1+1.6775)\\\\=(17.4225,\ 20.7775)\approx(17.42,\ 20.78)$

Hence, the 99% confidence interval for the population mean is (17.42, 20.78) .

7 0

3 years ago

The circumference of a circular field is 200.96 meters. What is the diameter of the field? Use 3.14.

artcher [175]

Answer:

1262.0288

Step-by-step explanation:

2×3.14×200.96

3 0

3 years ago

When commercial aircraft are inspected, wing cracks are reported as nonexistent, detectable, or critical. The history of a parti

Kamila [148]

Answer:

0.226

Step-by-step explanation:

Given that:

No wing crack (x) = 70%

Detectable wing crack (y) = 25%

Critical wing crack (z) = 5%

Number of samples (n) = 5

Probability that atleast a plane has critical crack:

1 - p(no critical crack)

Using the multinomial distribution calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0)

From the calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0) = 0.7741

1 - 0.7741 = 0.2259

= 0.226

7 0

3 years ago