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3 years ago

5

Which table of ordered pairs represents a proportional relationship?

1 answer:

spayn [35]3 years ago

6 0

I believe the answer is B

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$3000 deposit that earns 6% annual interest compounded quarterly

Lostsunrise [7]

Your interest would be $184.9 for 1 year so your total amount would be $3184.09

7 0

3 years ago

Suppose you have a pocketful of change. You have some pennies (p) and some quarters (q). One expression could be used to describ

faltersainse [42]

Answer:

13

1.57

Step-by-step explanation:

So we have two equations regarding the number of quarters <em>q</em> and the number of pennies <em>p:</em>

<em /> $p+q$ <em />

Which represents the total amount of coins and

$0.01p+0.25q$

Which represents the total amount of money in dollars.

So we are asked to evaluation each expression for the situation in which we have 6 quarters and 7 pennies. Thus, plug 6 in for <em>q</em> and 7 in for <em>p:</em>

<em /> $p+q\\(7)+(6)=13$ <em />

This tells us that we have 16 coins in total.

$0.01(7)+0.25(6)\\=0.07+1.50\\=1.57$

This tells us that we have a total amount of $1.57.

5 0

3 years ago

Read 2 more answers

F(x) = 1/x<br> g(x) = x - 4<br> Can you evaluate (gof)(0)? Explain why or why<br> not.

s344n2d4d5 [400]

(gof)(0) cannot be evaluated

<em><u>Solution:</u></em>

Given that,

$f(x) = \frac{1}{x}\\\\g(x) = x - 4$

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

$(g o f) (x) = g(\frac{1}{x})$

$\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4$

$(g o f) (x) = \frac{1}{x} - 4$

Now to find (gof)(0), substitute x = 0

$(g o f) (x) = \frac{1}{0} - 4$

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

6 0

3 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

What is the volume of the figure below, in cubic centimeters?<br><br> 756<br> 936<br> 1008<br> 1080

irina1246 [14]

936 I think is the best answer

8 0

3 years ago