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3 years ago

I will give brainliest answer

Mathematics

2 answers:

amid [387]3 years ago

8 0

Radius of the outer circle = 9cm

Area of a circle = πr²

= π×9×9

= 254.34cm²

Radius of the inner circle = 6cm

Area of a circle = πr²

= π×6×6

=113.04cm²

Therefore, area of the shaded region = 254.34-113.04

=141.30cm²

snow_tiger [21]3 years ago

5 0

Step-by-step explanation:

inner region

A=πr^2

A=π*6^2

A=π*36cm^2

A=113.09cm^2

shaded region(outer)

A=πr^2

A=π*9^2

A=π*81cm^2

A=254.46cm^2

Area of shaded region=254.46cm^2-113.09cm^2

=141.37cm^2

Mark brianliest if my answer suit your question

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babunello [35]

Answer:

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Step-by-step explanation:

A playing field is Rectangular is shape, hence,

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Hence we input these values in the formula and we have:

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2 years ago

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s344n2d4d5 [400]

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3 years ago

Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2

soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

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Given that line is passing through point (-5, 2) and (3, r)

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On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$