HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
1 answer:
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1. We need to get rid of those pesky parentheses. We do this by distributing the 3.
2. We need to get "n" by itself, so we add 9 to both sides.
3. Add like terms.
4. Now, we need to get rid of the -9, so we divide both sides by -9. Remember that dividing by negative numbers changes the direction of the "greater than or equal to" symbol.
5. We divide, and the negatives cancel.
I wrote the answer both ways so that I could tell what the number line needed to look like.
2. We need to get "n" by itself, so we add 9 to both sides.
3. Add like terms.
4. Now, we need to get rid of the -9, so we divide both sides by -9. Remember that dividing by negative numbers changes the direction of the "greater than or equal to" symbol.
5. We divide, and the negatives cancel.
I wrote the answer both ways so that I could tell what the number line needed to look like.
9514 1404 393
Answer:
(b) g, h, f
Step-by-step explanation:
The larger the magnitude of the vertical scale factor, the quicker the graph takes on higher values. That makes its appearance narrower.
Here, you want to list the functions in decreasing order of vertical scale factor:
g(x) . . . scale factor 4
h(x) . . . scale factor 2
f(x) . . . scale factor 1/3
Answer:
C(x) = $850 - $350x
Monthly Profit = -500x² + 1550x - 850
x = $1.55
the largest possible monthly profit = $351.25
Step-by-step explanation:
Given:
Demand equation:
q = -500x + 1200
where, q is the number of users who log on per month
x is the log-on fee you charge
Site maintenance fee = $10 per month
High-volume access fee = $0.70 per log-on
Now,
C(x) = $10 + ( $0.70 × q )
or
C(x) = $10 + ( $0.70 × (-500x + 1200) )
or
C(x) = $10 + ( - $350x + 840 )
or
C(x) = $850 - $350x
Total monthly income = qx
or
Total monthly income = ( -500x + 1200 ) × x
or
Total monthly income = -500x² + 1200x
now,
Profit = Income - cost
or
Monthly Profit = -500x² + 1200x - ( 850 - 350x )
or
Monthly Profit, P(x) = -500x² + 1550x - 850
For the largest possible monthly profit
= 0
or
=0
or
-2 × 500x + 1550 = 0
or
-1000x + 850 = 0
or
x = $1.55
Now,
the largest possible monthly profit will be at x = $1.55
substitute in the function of profit
P(1.55) = ( -500× 1.55² ) + ( 1550 × 1.55 ) - 850
or
the largest possible monthly profit = - 1201.25 + 2402.5 - 850
or
the largest possible monthly profit = $351.25