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kirza4 [7]
3 years ago
6

1. Which measurement represents the height of the parallelogram? (1 point) 6 m 4.2 m 3 m

Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

is numper

Step-by-step explanation:

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Answer:

  (a) at t=2, the particle is moving toward the origin

  (b) a(t) = 70(8 -9t^2)/(3t^2 +8)^3; a(2) = -0.245

  (c) the particle approaches x = 1/3 as t gets large

Step-by-step explanation:

(a) The function x(t) is negative for -3 < t < 3, so at t = 2, the particle is to the left of the origin.

The velocity of the particle is given by the derivative of the position function:

  x'(t)=\dfrac{(3t^2+8)(2t)-(t^2-9)(6t)}{(3t^2+8)^2}=\dfrac{70t}{(3t^2+8)^2}

Then, at t=2, the expression is positive, indicating the particle is moving toward the origin.

__

(b) The acceleration is the derivative of the velocity, so is ...

  a(t)=\dfrac{70(3t^2+8)^2-(70t)(12t)(3t^2+8)}{(3t^2+8)^4}=\dfrac{70(3t^2+8-12t^2)}{(3t^2+8)^3}\\\\\boxed{a(t)=\dfrac{70(8-9t^2)}{(3t^2+8)^3}}

Then at t=2, the acceleration is ...

  a(2) = 70(8 -9·4)/(3·4+8)^3 = 70(-28)/8000

  a(2) = -0.245

__

(c) As t gets large, the value of x(t) approaches t^2/(3t^2) = 1/3.

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