All categories

3 years ago

What do you do when you have two exponent in the same parentheses adding to each other

Mathematics

2 answers:

morpeh [17]3 years ago

3 0

Answer:

Raise the power

Step-by-step explanation:

ArbitrLikvidat [17]3 years ago

3 0

Answer: my answer would be to just add the exponents see if it works hope this helps

Step-by-step explanation:

You might be interested in

Someone help me please please please I really need this

Inga [223]

Answer:

Step-by-step explanation:

rs st tw rt rw sw

sr sw tr st tw

tr and tw

sr and st

I'll depend on you to add the proper markings on the answer.

7 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

4 years ago

Find the number of 4-digit numbers that contain exactly two even and two odd digits.

Dvinal [7]

Answer:

2,435

Step-by-step explanation:

find two even and two odd

7 0

3 years ago

Is there enough information given to find the value of X. Explain your reasoning.

Anna007 [38]

With what you've jus given me, no. is there an equation or something to go along with this question?

4 0

3 years ago

Given 14 – 2(x + 8) = 5x – (3x – 34), prove x = -9 what are the steps to be able to prove x=-9

Veronika [31]

Answer: x = -9

steps

Simplifying

14 + -2(x + 8) = 5x + -1(3x + -34)

Reorder the terms:

14 + -2(8 + x) = 5x + -1(3x + -34)

14 + (8 * -2 + x * -2) = 5x + -1(3x + -34)

14 + (-16 + -2x) = 5x + -1(3x + -34)

Combine like terms: 14 + -16 = -2

-2 + -2x = 5x + -1(3x + -34)

Reorder the terms:

-2 + -2x = 5x + -1(-34 + 3x)

-2 + -2x = 5x + (-34 * -1 + 3x * -1)

-2 + -2x = 5x + (34 + -3x)

Reorder the terms:

-2 + -2x = 34 + 5x + -3x

Combine like terms: 5x + -3x = 2x

-2 + -2x = 34 + 2x

Solving

-2 + -2x = 34 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

-2 + -2x + -2x = 34 + 2x + -2x

Combine like terms: -2x + -2x = -4x

-2 + -4x = 34 + 2x + -2x

Combine like terms: 2x + -2x = 0

-2 + -4x = 34 + 0

-2 + -4x = 34

Add '2' to each side of the equation.

-2 + 2 + -4x = 34 + 2

Combine like terms: -2 + 2 = 0

0 + -4x = 34 + 2

-4x = 34 + 2

Combine like terms: 34 + 2 = 36

-4x = 36

Divide each side by '-4'.

x = -9

7 0

3 years ago