You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
2 metre= 1millimetre
Step-by-step explanation:
From the measurement of the house The front patio, is 14 meters wide in real life, is 7 millimeters wide in the drawing
Real life= 14 meters
Drawing= 7 millimeters,
The scale he used is 2 metre= 1millimetre
Which means he magnify the drawing by scale of 2 metre to get the real life structure.
✓Let us clarify it
14 meters = 7 millimeters
2 metre= x millimeter
If we cross multiply
7 millimeters× 2 metre= 14 metre × X millimeters
Make X subject of the formula we have
X= 1millimetres
Answer:
1995.26
Step-by-step explanation:
It usually works to follow instructions:
3.3 = log(x) . . . . . substitute known values into the equation
10^3.3 = x . . . . . take antilogs
1995.26 = x . . . . simplify, round to hundredths
Answer:
20/49
Step-by-step explanation:
Answer:
2.20 per 1000 so it's gonna be $2.20/1000 per 1. So 4500 take $2.20/1000*4500=...
Step-by-step explanation:
