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nirvana33 [79]
3 years ago
5

9r^6/ 5r^3g^2, 5n^5c^-6 times 2n^-5c^3, and 9g^-4yA^4/3g^6y^-2 using properties of exponents, all this for 10 points

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

Step-by-step explanation:

5n⁵c⁻⁵ *  2n⁻⁵c³ = (5*2)*n⁵⁺⁽⁻⁵⁾ * c⁻⁶⁺³

                          =10*n° *c⁻³

                           = 10c⁻³               (n° = 1}

a^{m}*a^{n}=a^{m+n}\\\\\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\frac{9r^{6}}{5r^{3}g^{2}}=\frac{9}{5g^{2}}*r^{6-3}\\\\=\frac{9r^{3}}{5g^{2}}\\\\\\\\\frac{9g^{-4}y^{4}}{3g^{6}y^{-2}}=\frac{9}{3}*g^{-4-6}*y^{4-(-2)}\\\\=3*g^{-10}*y^{4+2}\\\\=3g^{-10}*y^{6}\\\\=\frac{3y^{6}}{g^{10}}

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