Answer:
- 2 < x < 2
Step-by-step explanation:
Given
- 3 < 2x + 1 < 5 ( subtract 1 from each interval )
- 4 < 2x < 4 ( divide each interval by 2 )
- 2 < x < 2
That would be a:-
13x + 32
-----------
13x
F(6)=2^6
F=2^6
The answer is
F=64
The given equation is-

First, we move the independent term to the other side.

Now, we have to use the quadratic equation to find the solutions.-
![x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Where, a = 1, b = -10, and c = 34.
Replacing these values in the formula, we have.
![\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(1)(34)}}{2(1)} \\ x_{1,2}=\frac{10\pm\sqrt[]{100-136}}{2}=\frac{10\pm\sqrt[]{-36}}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x_%7B1%2C2%7D%3D%5Cfrac%7B-%28-10%29%5Cpm%5Csqrt%5B%5D%7B%28-10%29%5E2-4%281%29%2834%29%7D%7D%7B2%281%29%7D%20%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B100-136%7D%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B-36%7D%7D%7B2%7D%20%5Cend%7Bgathered%7D)
But, there's no square root of -36 because it's a negative. To solve this issue, we use complex numbers that way, we would have solutions.
![x_{1,2}=\frac{10\pm\sqrt[]{36}i}{2}=\frac{10\pm6i}{2}=5\pm3i](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B36%7Di%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm6i%7D%7B2%7D%3D5%5Cpm3i)
<h2>Therefore, the solutions are</h2>

The right answer is B.
3y = 2x - 6
y = 2/3x - 2
y = 2/3x + c , ( - 2, 5 )
5 = 2/3 ( -2 ) + c
3c = - 6
c = - 2
y = 2/3x - 2
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