Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²
Yo answer to yo question is d
Answer:
144°
Step-by-step explanation:
step 1
Find the measure of the central angle of the regular pentagon
Divide 360 degrees by 5 (the number of sides)
Let
c----> the center of the pentagon
we know that
m∠ECA=72°
m∠ACB=72°
therefore
m∠ECB=m∠ECA+m∠ACB
substitute the values
m∠ECB=72°+72°=144°
The measure of angle ECB is equal to the degrees that the pentagon rotate
Answer:
x=π/2 ,3π/2
Step-by-step explanation:
cot x(csc x+1)=0
either cot x=0
tanx=∞=tan (π/2)
x=π/2
or csc x=-1
or sin x=-1=-sin (π/2)=sin (π+π/2)=sin (3π/2)
x=3π/2
Please enclose the "nt" inside parentheses: <span>A(t)=P(1+r/n)^(nt).
Then: A = $500*(1+0.06/12)^(5*12) = $641.68</span>
