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3 years ago

I will give brainliest!

Mathematics

1 answer:

AVprozaik [17]3 years ago

5 0

Answer: Its B

Step-by-step explanation:

You might be interested in

Given f(x)=6x+2, find f(x+3).

Finger [1]

Answer:

f(x+3) is 6x + 20

Step-by-step explanation:

${ \sf{f(x) = 6x + 2}} \\ { \sf{f(x + 3) = 6(x + 3) + 2}} \\ = { \sf{6x + 20}}$

3 0

3 years ago

Can anyone help me??

Tasya [4]

Your in luck! I was just learning these percent things today 'xD but Not in luck at the same time. I will answer the 2 questions that's the most I can do.

1. $17.50 with a 7% sales tax

Answer: 17.50 times .07 equals 1.23

17.50 plus 1.23 equals 18.73

The answer is $18.73

2. 21.95 with a 4.25% sales tax

Answer: 21.95+4.25=26.20

Hope this helps!! :D this took me a while to figure out and used a bit of my time. So I hope the time was worth it! :)

5 0

4 years ago

Solve for x: 2|х - 3 |+1 = 7

Rasek [7]

When using problems like this use mathaway love

5 0

3 years ago

Find the product. (−x−3)(2x2+5x+8)=

harina [27]

$( - x - 3)(2 {x}^{2} + 5x + 8) = \\ = - 2 {x}^{3} - 5 {x}^{2} - 8x - 6 {x}^{2} - 15x - 24 = \\ = - 2 {x}^{3} - 11 {x}^{2} - 23x - 24$

3 0

4 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

4 years ago