Answer:
13! or 6227020800
Step-by-step explanation:
With no restrictions, we can figure out the answer to be 13! by the following analysis:
For the first position in line, there are 13 different students who could fill that spot. If we fill it and proceed to the next position in line, there are now only 12 students left who can fill it, since one is already in line. Then the next position only has 11 possibilities, and the next 10, and so on.
Multiplying all of this together gives us 13*12*11*10*9*8*7*6*5*4*3*2*1 or 13!
8*6=48. 8*7=56. So the highest multiplication you can go without exceeding the value of 52 is 8*6. You then need to subtract 52 by 48 to find the remainder. 52-48=4. So the answer would be 48 remainder 4
The answer to the problem is x - 1
Answer: DO you have any options that can help me answer it?
Step-by-step explanation:
When a number is 3 times a first number. A third number is 100 more than the first number and the sum of the three numbers is 450, the numbers are 70, 170 and 210.
<h3>How to calculate the numbers?</h3>
Let the first number = x
Second number = 3x
Third number = x + 100
Sum = 450
The numbers will be:
x + 3x + x + 100 = 450
5x + 100 = 450
5x = 450 - 100
5x = 350
Divide
x = 350 / 5
x = 70
First number = 70
Second number = 3x = 3 × 70 = 210
Third number = x + 100 = 70 + 100 = 170
Therefore, the numbers are 70, 170 and 210.
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 450 , find the numbers.