Answer:
1/6
Step-by-step explanation:
When trying to calculate the probability of a sequence of events you need to multiply the probability of the first event happening by the probability of the second event happening. There are a total of 4 numbers (2,3,4,5) and only one is a 2. Therefore the probability of the first pick being a 2 is 1/4. Now there are only 3 cards left (3,4,5) and only 2 numbers are greater than 3 so the probability of picking one of these cards is 2/3. Now that we have both of these probabilities we simply multiply them together.
1/4 * 2/3 = 2/12 or 1/6
Therefore, the probability of picking a 2 and then picking a number greater than 3 is 1/6
Answer:
(22, 9)
Step-by-step explanation:
The positive difference of two integers is 13. The sum of the larger number and the square of the smaller is 103. Give your solution(s) as ordered pair (larger, smaller). I'll call the two integers a and b.
a - b = 13 a + b² = 103
<u> +b +b</u>
a = 13 + b plug this into the second equation
a + b² = 103
(13+b) + b² = 103 subtract 103 from both sides to get one side equal to zero
<u>-103 -103</u>
b² + b - 90 = 0 what factors (two numbers multiply) to -90 that also add up
to 1? The only two that work are -9 and 10.
(b-9)(b+10) = 0 so b-9 = 0 or b+10 = 0
<u>+9 +9</u> or <u>-10 -10</u>
b = 9 or b = -10 but both numbers must be positive
b = 9 and a = 13 + b so a = 13 + 9 = 22
(22, 9)
Answer:
A
Step-by-step explanation:
Answer: 0.31
Step-by-step explanation:
Let A denotes the event of Tampa Bay Buccaneers will score a touchdown on their opening drive and B denote the event that their defense will have 3 or more sacks in the game.
Given : P(A)=0.14 P(B) = 0.31 P(A or B)=0.14
Formula : P(A and B)= P(A) + P(B) - P(A or B)
Now, the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game will be :-
P(A and B)= 0.14 + 0.31 - 0.14=0.31
Hence, the required probability : 0.31
Answer:
do you have a picture?
Step-by-step explanation:
I can't go off of just that (not enough info)
