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3 years ago

Please help its a test!

Mathematics

1 answer:

marishachu [46]3 years ago

7 0

Answer: the answer is A :)

Step-by-step explanation:

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What is -2 × 1 1/4=

RoseWind [281]

Answer: -11/2

Step-by-step explanation:

Just set it up so it looks like this:

-2/1 x 11/4 and multiply across the top, which would be -22 and then the across the bottom, which would equal 4. So it’s -22/4. BUT you can simplify it down to -11/2 by dividing both sides of the fraction by 2. So then answer is -11/2

Hope that makes sense! :)

5 0

3 years ago

The weights of 1250 pumpkins are normally distributed with mean of 28 pounds and a standard deviation of 6 pounds. About how man

Mekhanik [1.2K]

Kropot72
kropot72 3 years ago
This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
Can use the table to find the cumulative probability for z = 1.00 and post the result? If you do this we can do the next simple steps.

5 0

3 years ago

Rebecca makes an A in a 4-credit math course , a B in a 3-credit English course, a C in a 3-credit science course, a B in the as

Elan Coil [88]

Answer: b

Step-by-step explanation: krusty crab pizza is the pizza for you and me

4 0

3 years ago

Where are the asymptotes of f(x) = tan (4x-pi) from x=0 to x= pi/2

professor190 [17]

Step-by-step explanation:

the asymptotes of f(x) :

(4x-π) = π/2

4x = 3π/2 => x = 3π/8

(4x-π) = 3π/2

4x=5π/2 => x = 5π/8

the answer is

D. X= 3pi/8, x=5pi/8

5 0

3 years ago

Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A

nikdorinn [45]

Answer:

a) $A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$ , b) $B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$ , c) $C = \{\forall x \in M\,|\,xI \}$ , d) $D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$ , e) $E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

$A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$

b) x - A student, M - Set of students of discrete math class, y - A perfect grade, H - Midterm I.

$B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$

c) x - A student, M - Set of students of discrete math class, I - loves discrete math.

$C = \{\forall x \in M\,|\,xI \}$

d) x - A student, M - Set of students of discrete math class, J - has been in, y - a state, U - Set of states of the United States of America.

$D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$

e) x - A student, M - Set of students of discrete math class, J - has been in, y - a city, V - At least one state of the United States of America, U - Set of states of the United States of America.

$E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

5 0

3 years ago