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telo118 [61]
3 years ago
14

Stephen has some money in a box ,if 3/8 of the money is #4.80,how much does he have in the box?​

Mathematics
1 answer:
cupoosta [38]3 years ago
3 0
If 3/8 is #4.80 then 1/8 would be #1.60 and 8/8 is #12.80
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Finding volume of a rectangular prism
torisob [31]

Answer:

uhh.... you are missing some part of your question

Step-by-step explanation:

6 0
2 years ago
HEEELP
Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}

Here, \sqrt{x+5}\ \text{is always greater than equal to 0}\\\Rightarrow x+5\geq 0\\\Rightarrow x\geq -5\quad \ldots(i)

To get f\left(g(x)\right), replace x in f(x) by g(x)\ \text{i.e. by}\ \sqrt{x+5}

\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)

Using (i) and (ii)  it can be concluded that the domain of f\left(g(x)\right) is all real numbers except 0.

Therefore, its domain is given by

x\in [-5,4)\cup (4,\infty)

Option (c) is correct.

5 0
3 years ago
Does someone mind helping me with this problem? Thank you!
Jet001 [13]

Answer:

875 ft²

Step-by-step explanation:

Finding area of similar rectangles:

Scale factor = EF : AB

                    = 25 : 5

                    = 5 : 1

\sf \dfrac{Area \ of \ bigger \ rectangle}{Area \ of \ smaller \ rectangle}= (Scale \ factor)^2

\dfrac{Area \ of \ bigger \  rectangle}{35} =\left(\dfrac{5}{1}\right)^2

\text{Area of bigger rectangle = $\dfrac{25}{1}*35$}

Area or rectangle EFGH = 875 ft²

4 0
2 years ago
Read 2 more answers
Transform x2 + 6x + 8 = 0 into the form (x − p)2 = q?
liraira [26]
So hmmm x²+6x+8=0

alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0

notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?

let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute!  2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"

alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0

so if we add 3², we also have to subtract 3², let's do so

(x² + 6x +3² - 3²) + 8 = 0

(x² + 6x +3²) + 8 - 3² = 0

(x+3)²=3² - 8

(x+3)² = 1
5 0
3 years ago
Read 2 more answers
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inessss [21]

May you explain what is being asked?


5 0
3 years ago
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